SPI: use mutex not semaphore
Make spi_write_then_read() use a mutex not a binary semaphore. Signed-off-by: David Brownell <dbrownell@users.sourceforge.net> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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committed by
Linus Torvalds
parent
f8fcc93319
commit
068f407086
@@ -589,7 +589,7 @@ int spi_write_then_read(struct spi_device *spi,
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const u8 *txbuf, unsigned n_tx,
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const u8 *txbuf, unsigned n_tx,
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u8 *rxbuf, unsigned n_rx)
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u8 *rxbuf, unsigned n_rx)
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{
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{
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static DECLARE_MUTEX(lock);
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static DEFINE_MUTEX(lock);
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int status;
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int status;
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struct spi_message message;
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struct spi_message message;
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@@ -615,7 +615,7 @@ int spi_write_then_read(struct spi_device *spi,
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}
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}
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/* ... unless someone else is using the pre-allocated buffer */
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/* ... unless someone else is using the pre-allocated buffer */
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if (down_trylock(&lock)) {
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if (!mutex_trylock(&lock)) {
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local_buf = kmalloc(SPI_BUFSIZ, GFP_KERNEL);
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local_buf = kmalloc(SPI_BUFSIZ, GFP_KERNEL);
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if (!local_buf)
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if (!local_buf)
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return -ENOMEM;
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return -ENOMEM;
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@@ -634,7 +634,7 @@ int spi_write_then_read(struct spi_device *spi,
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}
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}
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if (x[0].tx_buf == buf)
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if (x[0].tx_buf == buf)
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up(&lock);
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mutex_unlock(&lock);
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else
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else
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kfree(local_buf);
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kfree(local_buf);
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