Btrfs: don't allow a subvol to be deleted if it is the default subovl
Eric pointed out that btrfs will happily allow you to delete the default subvol. This is a problem obviously since the next time you go to mount the file system it will freak out because it can't find the root. Fix this by adding a check to see if our default subvol points to the subvol we are trying to delete, and if it does not allowing it to happen. Thanks, Signed-off-by: Josef Bacik <jbacik@fusionio.com> Signed-off-by: Chris Mason <chris.mason@fusionio.com>
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@@ -1726,13 +1726,28 @@ out:
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static noinline int may_destroy_subvol(struct btrfs_root *root)
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static noinline int may_destroy_subvol(struct btrfs_root *root)
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{
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{
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struct btrfs_path *path;
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struct btrfs_path *path;
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struct btrfs_dir_item *di;
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struct btrfs_key key;
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struct btrfs_key key;
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u64 dir_id;
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int ret;
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int ret;
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path = btrfs_alloc_path();
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path = btrfs_alloc_path();
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if (!path)
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if (!path)
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return -ENOMEM;
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return -ENOMEM;
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/* Make sure this root isn't set as the default subvol */
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dir_id = btrfs_super_root_dir(root->fs_info->super_copy);
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di = btrfs_lookup_dir_item(NULL, root->fs_info->tree_root, path,
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dir_id, "default", 7, 0);
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if (di && !IS_ERR(di)) {
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btrfs_dir_item_key_to_cpu(path->nodes[0], di, &key);
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if (key.objectid == root->root_key.objectid) {
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ret = -ENOTEMPTY;
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goto out;
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}
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btrfs_release_path(path);
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}
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key.objectid = root->root_key.objectid;
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key.objectid = root->root_key.objectid;
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key.type = BTRFS_ROOT_REF_KEY;
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key.type = BTRFS_ROOT_REF_KEY;
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key.offset = (u64)-1;
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key.offset = (u64)-1;
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