x86/i386: Make sure stack-protector segment base is cache aligned
The Intel Optimization Reference Guide says: In Intel Atom microarchitecture, the address generation unit assumes that the segment base will be 0 by default. Non-zero segment base will cause load and store operations to experience a delay. - If the segment base isn't aligned to a cache line boundary, the max throughput of memory operations is reduced to one [e]very 9 cycles. [...] Assembly/Compiler Coding Rule 15. (H impact, ML generality) For Intel Atom processors, use segments with base set to 0 whenever possible; avoid non-zero segment base address that is not aligned to cache line boundary at all cost. We can't avoid having a non-zero base for the stack-protector segment, but we can make it cache-aligned. Signed-off-by: Jeremy Fitzhardinge <jeremy.fitzhardinge@citrix.com> Cc: <stable@kernel.org> LKML-Reference: <4AA01893.6000507@goop.org> Signed-off-by: Ingo Molnar <mingo@elte.hu>
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Ingo Molnar
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23386d63bb
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1ea0d14e48
@ -78,14 +78,14 @@ static __always_inline void boot_init_stack_canary(void)
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#ifdef CONFIG_X86_64
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percpu_write(irq_stack_union.stack_canary, canary);
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#else
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percpu_write(stack_canary, canary);
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percpu_write(stack_canary.canary, canary);
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#endif
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}
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static inline void setup_stack_canary_segment(int cpu)
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{
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#ifdef CONFIG_X86_32
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unsigned long canary = (unsigned long)&per_cpu(stack_canary, cpu) - 20;
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unsigned long canary = (unsigned long)&per_cpu(stack_canary, cpu);
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struct desc_struct *gdt_table = get_cpu_gdt_table(cpu);
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struct desc_struct desc;
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