debugfs: remove module_exit()
debugfs can't be a module, so module_exit() is meaningless for it. Signed-off-by: WANG Cong <amwang@redhat.com> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
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committed by
Greg Kroah-Hartman
parent
345279bc10
commit
1f7da214e2
@@ -13,9 +13,6 @@
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*
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*
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*/
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*/
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/* uncomment to get debug messages from the debug filesystem, ah the irony. */
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/* #define DEBUG */
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#include <linux/module.h>
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#include <linux/module.h>
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#include <linux/fs.h>
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#include <linux/fs.h>
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#include <linux/mount.h>
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#include <linux/mount.h>
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@@ -540,17 +537,5 @@ static int __init debugfs_init(void)
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return retval;
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return retval;
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}
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}
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static void __exit debugfs_exit(void)
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{
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debugfs_registered = false;
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simple_release_fs(&debugfs_mount, &debugfs_mount_count);
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unregister_filesystem(&debug_fs_type);
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kobject_put(debug_kobj);
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}
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core_initcall(debugfs_init);
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core_initcall(debugfs_init);
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module_exit(debugfs_exit);
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MODULE_LICENSE("GPL");
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