memblock: Remove memblock_type.size and add memblock.memory_size instead
Right now, both the "memory" and "reserved" memblock_type structures have a "size" member. It represents the calculated memory size in the former case and is unused in the latter. This moves it out to the main memblock structure instead Signed-off-by: Benjamin Herrenschmidt <benh@kernel.crashing.org>
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@ -49,7 +49,7 @@ void memblock_dump_all(void)
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return;
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pr_info("MEMBLOCK configuration:\n");
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pr_info(" memory.size = 0x%llx\n", (unsigned long long)memblock.memory.size);
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pr_info(" memory size = 0x%llx\n", (unsigned long long)memblock.memory_size);
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memblock_dump(&memblock.memory, "memory");
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memblock_dump(&memblock.reserved, "reserved");
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@ -123,10 +123,10 @@ void __init memblock_analyze(void)
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{
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int i;
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memblock.memory.size = 0;
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memblock.memory_size = 0;
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for (i = 0; i < memblock.memory.cnt; i++)
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memblock.memory.size += memblock.memory.regions[i].size;
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memblock.memory_size += memblock.memory.regions[i].size;
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}
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static long memblock_add_region(struct memblock_type *type, phys_addr_t base, phys_addr_t size)
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@ -423,7 +423,7 @@ phys_addr_t __init __memblock_alloc_base(phys_addr_t size, phys_addr_t align, ph
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/* You must call memblock_analyze() before this. */
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phys_addr_t __init memblock_phys_mem_size(void)
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{
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return memblock.memory.size;
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return memblock.memory_size;
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}
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phys_addr_t memblock_end_of_DRAM(void)
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