rcu: Avoid waking up CPUs having only kfree_rcu() callbacks
When CONFIG_RCU_FAST_NO_HZ is enabled, RCU will allow a given CPU to enter dyntick-idle mode even if it still has RCU callbacks queued. RCU avoids system hangs in this case by scheduling a timer for several jiffies in the future. However, if all of the callbacks on that CPU are from kfree_rcu(), there is no reason to wake the CPU up, as it is not a problem to defer freeing of memory. This commit therefore tracks the number of callbacks on a given CPU that are from kfree_rcu(), and avoids scheduling the timer if all of a given CPU's callbacks are from kfree_rcu(). Signed-off-by: Paul E. McKenney <paul.mckenney@linaro.org> Signed-off-by: Paul E. McKenney <paulmck@linux.vnet.ibm.com>
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committed by
Paul E. McKenney
parent
0bb7b59d6e
commit
486e259340
@ -76,16 +76,18 @@ static inline void debug_rcu_head_unqueue(struct rcu_head *head)
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extern void kfree(const void *);
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static inline void __rcu_reclaim(char *rn, struct rcu_head *head)
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static inline bool __rcu_reclaim(char *rn, struct rcu_head *head)
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{
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unsigned long offset = (unsigned long)head->func;
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if (__is_kfree_rcu_offset(offset)) {
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RCU_TRACE(trace_rcu_invoke_kfree_callback(rn, head, offset));
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kfree((void *)head - offset);
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return 1;
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} else {
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RCU_TRACE(trace_rcu_invoke_callback(rn, head));
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head->func(head);
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return 0;
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}
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}
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