m68k: Mac IRQ prep
Make sure that there are no slot IRQs asserted before leaving the nubus handler. If there are and we don't then the nubus gets wedged because this prevents a CA1 transition, which means no more nubus IRQs. Make the interrupt dispatch loops terminate sooner. Explicitly initialise the VIA latches to make the code more easily understood. Also some cleanups. Signed-off-by: Finn Thain <fthain@telegraphics.com.au> Signed-off-by: Geert Uytterhoeven <geert@linux-m68k.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
committed by
Linus Torvalds
parent
647b804c82
commit
67dfb153a3
@@ -131,11 +131,8 @@ irqreturn_t psc_irq(int irq, void *dev_id)
|
||||
{
|
||||
int pIFR = pIFRbase + ((int) dev_id);
|
||||
int pIER = pIERbase + ((int) dev_id);
|
||||
int base_irq;
|
||||
int irq_bit,i;
|
||||
unsigned char events;
|
||||
|
||||
base_irq = irq << 3;
|
||||
int irq_num;
|
||||
unsigned char irq_bit, events;
|
||||
|
||||
#ifdef DEBUG_IRQS
|
||||
printk("psc_irq: irq %d pIFR = 0x%02X pIER = 0x%02X\n",
|
||||
@@ -146,14 +143,18 @@ irqreturn_t psc_irq(int irq, void *dev_id)
|
||||
if (!events)
|
||||
return IRQ_NONE;
|
||||
|
||||
for (i = 0, irq_bit = 1 ; i < 4 ; i++, irq_bit <<= 1) {
|
||||
if (events & irq_bit) {
|
||||
irq_num = irq << 3;
|
||||
irq_bit = 1;
|
||||
do {
|
||||
if (events & irq_bit) {
|
||||
psc_write_byte(pIER, irq_bit);
|
||||
psc_write_byte(pIFR, irq_bit);
|
||||
m68k_handle_int(base_irq + i);
|
||||
m68k_handle_int(irq_num);
|
||||
psc_write_byte(pIER, irq_bit | 0x80);
|
||||
}
|
||||
}
|
||||
irq_num++;
|
||||
irq_bit <<= 1;
|
||||
} while (events >= irq_bit);
|
||||
return IRQ_HANDLED;
|
||||
}
|
||||
|
||||
|
Reference in New Issue
Block a user