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[PATCH] sched: don't print migration cost when only 1 CPU

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If only a single CPU is present, printing this doesn't make much sense.

Signed-off-by: Dave Jones <davej@redhat.com>
Acked-by: Ingo Molnar <mingo@elte.hu>
Acked-by: Nick Piggin <nickpiggin@yahoo.com.au>
Signed-off-by: Andrew Morton <akpm@osdl.org>
Signed-off-by: Linus Torvalds <torvalds@osdl.org>
This commit is contained in:
Dave Jones
2006-10-03 01:14:07 -07:00
committed by Linus Torvalds
parent a616058b78
commit 7473264643
1 changed files with 8 additions and 6 deletions
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2
kernel/sched.c
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@@ -5977,6 +5977,7 @@ static void calibrate_migration_costs(const cpumask_t *cpu_map)
#endif #endif
); );
if (system_state == SYSTEM_BOOTING) { if (system_state == SYSTEM_BOOTING) {
if (num_online_cpus() > 1) {
printk("migration_cost="); printk("migration_cost=");
for (distance = 0; distance <= max_distance; distance++) { for (distance = 0; distance <= max_distance; distance++) {
if (distance) if (distance)
@@ -5985,6 +5986,7 @@ static void calibrate_migration_costs(const cpumask_t *cpu_map)
} }
printk("\n"); printk("\n");
} }
}
j1 = jiffies; j1 = jiffies;
if (migration_debug) if (migration_debug)
printk("migration: %ld seconds\n", (j1-j0)/HZ); printk("migration: %ld seconds\n", (j1-j0)/HZ);