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freezer: unexport refrigerator() and update try_to_freeze() slightly

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There is no reason to export two functions for entering the
refrigerator.  Calling refrigerator() instead of try_to_freeze()
doesn't save anything noticeable or removes any race condition.

* Rename refrigerator() to __refrigerator() and make it return bool
  indicating whether it scheduled out for freezing.

* Update try_to_freeze() to return bool and relay the return value of
  __refrigerator() if freezing().

* Convert all refrigerator() users to try_to_freeze().

* Update documentation accordingly.

* While at it, add might_sleep() to try_to_freeze().

Signed-off-by: Tejun Heo <tj@kernel.org>
Cc: Samuel Ortiz <samuel@sortiz.org>
Cc: Chris Mason <chris.mason@oracle.com>
Cc: "Theodore Ts'o" <tytso@mit.edu>
Cc: Steven Whitehouse <swhiteho@redhat.com>
Cc: Andrew Morton <akpm@linux-foundation.org>
Cc: Jan Kara <jack@suse.cz>
Cc: KONISHI Ryusuke <konishi.ryusuke@lab.ntt.co.jp>
Cc: Christoph Hellwig <hch@infradead.org>
This commit is contained in:
Tejun Heo
2011-11-21 12:32:22 -08:00
parent 3a7cbd50f7
commit a0acae0e88
15 changed files with 37 additions and 39 deletions
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3
fs/ext4/super.c
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@@ -2882,8 +2882,7 @@ cont_thread:
}
mutex_unlock(&eli->li_list_mtx);
if (freezing(current))
refrigerator();
try_to_freeze();
cur = jiffies;
if ((time_after_eq(cur, next_wakeup)) ||