UBI: get rid of ubi_ltree_slab

This slab cache is not really needed since the number of objects
is low and the constructor does not make much sense because we
allocate oblects when doint I/O, which is way slower then allocation.

Suggested-by: Arnd Bergmann <arnd@arndb.de>
Signed-off-by: Artem Bityutskiy <Artem.Bityutskiy@nokia.com>
This commit is contained in:
Artem Bityutskiy
2008-01-16 12:11:54 +02:00
parent 4fac9f6984
commit b9a06623d9
3 changed files with 8 additions and 33 deletions

View File

@ -137,10 +137,12 @@ static struct ubi_ltree_entry *ltree_add_entry(struct ubi_device *ubi,
{
struct ubi_ltree_entry *le, *le1, *le_free;
le = kmem_cache_alloc(ubi_ltree_slab, GFP_NOFS);
le = kmalloc(sizeof(struct ubi_ltree_entry), GFP_NOFS);
if (!le)
return ERR_PTR(-ENOMEM);
le->users = 0;
init_rwsem(&le->mutex);
le->vol_id = vol_id;
le->lnum = lnum;
@ -188,7 +190,7 @@ static struct ubi_ltree_entry *ltree_add_entry(struct ubi_device *ubi,
spin_unlock(&ubi->ltree_lock);
if (le_free)
kmem_cache_free(ubi_ltree_slab, le_free);
kfree(le_free);
return le;
}
@ -236,7 +238,7 @@ static void leb_read_unlock(struct ubi_device *ubi, int vol_id, int lnum)
up_read(&le->mutex);
if (free)
kmem_cache_free(ubi_ltree_slab, le);
kfree(le);
}
/**
@ -292,7 +294,7 @@ static int leb_write_trylock(struct ubi_device *ubi, int vol_id, int lnum)
free = 0;
spin_unlock(&ubi->ltree_lock);
if (free)
kmem_cache_free(ubi_ltree_slab, le);
kfree(le);
return 1;
}
@ -321,7 +323,7 @@ static void leb_write_unlock(struct ubi_device *ubi, int vol_id, int lnum)
up_write(&le->mutex);
if (free)
kmem_cache_free(ubi_ltree_slab, le);
kfree(le);
}
/**