d_path: Make seq_path() use a struct path argument

seq_path() is always called with a dentry and a vfsmount from a struct path.
Make seq_path() take it directly as an argument.

Signed-off-by: Jan Blunck <jblunck@suse.de>
Cc: Christoph Hellwig <hch@lst.de>
Cc: Al Viro <viro@zeniv.linux.org.uk>
Cc: "J. Bruce Fields" <bfields@fieldses.org>
Cc: Neil Brown <neilb@suse.de>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Jan Blunck
2008-02-14 19:38:43 -08:00
committed by Linus Torvalds
parent e83aece3af
commit c32c2f63a9
9 changed files with 16 additions and 17 deletions

View File

@@ -342,13 +342,12 @@ int seq_printf(struct seq_file *m, const char *f, ...)
}
EXPORT_SYMBOL(seq_printf);
int seq_path(struct seq_file *m,
struct vfsmount *mnt, struct dentry *dentry,
char *esc)
int seq_path(struct seq_file *m, struct path *path, char *esc)
{
if (m->count < m->size) {
char *s = m->buf + m->count;
char *p = d_path(dentry, mnt, s, m->size - m->count);
char *p = d_path(path->dentry, path->mnt, s,
m->size - m->count);
if (!IS_ERR(p)) {
while (s <= p) {
char c = *p++;